Base | Representation |
---|---|
bin | 111100100011001111… |
… | …0011110011110001011 |
3 | 110102122010001012100010 |
4 | 1321012132132132023 |
5 | 4112301020210011 |
6 | 135422520243003 |
7 | 12252204526554 |
oct | 1710636363613 |
9 | 412563035303 |
10 | 130031413131 |
11 | 501673852a4 |
12 | 2124b310463 |
13 | c353552a99 |
14 | 641772532b |
15 | 35b09bb1a6 |
hex | 1e4679e78b |
130031413131 has 4 divisors (see below), whose sum is σ = 173375217512. Its totient is φ = 86687608752.
The previous prime is 130031413097. The next prime is 130031413159. The reversal of 130031413131 is 131314130031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130031413131 - 221 = 130029315979 is a prime.
It is a super-2 number, since 2×1300314131312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130031413098 and 130031413107.
It is not an unprimeable number, because it can be changed into a prime (130031413931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21671902186 + ... + 21671902191.
It is an arithmetic number, because the mean of its divisors is an integer number (43343804378).
Almost surely, 2130031413131 is an apocalyptic number.
130031413131 is a deficient number, since it is larger than the sum of its proper divisors (43343804381).
130031413131 is an equidigital number, since it uses as much as digits as its factorization.
130031413131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43343804380.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 130031413131 its reverse (131314130031), we get a palindrome (261345543162).
The spelling of 130031413131 in words is "one hundred thirty billion, thirty-one million, four hundred thirteen thousand, one hundred thirty-one".
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