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1300320003003 = 37547113199269
BaseRepresentation
bin10010111011000001000…
…111001010001110111011
311121022100112111021211020
4102323001013022032323
5132301023410044003
62433205254233523
7162642066441630
oct22730107121673
94538315437736
101300320003003
1146150a81918a
121900166558a3
13958094a9b28
1446d15c88187
1523c57085d53
hex12ec11ca3bb

1300320003003 has 16 divisors (see below), whose sum is σ = 1985062398720. Its totient is φ = 741681603936.

The previous prime is 1300320003001. The next prime is 1300320003067. The reversal of 1300320003003 is 3003000230031.

It is not a de Polignac number, because 1300320003003 - 21 = 1300320003001 is a prime.

It is a super-3 number, since 3×13003200030033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (1300320003001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56588148 + ... + 56611121.

It is an arithmetic number, because the mean of its divisors is an integer number (124066399920).

Almost surely, 21300320003003 is an apocalyptic number.

1300320003003 is a deficient number, since it is larger than the sum of its proper divisors (684742395717).

1300320003003 is a wasteful number, since it uses less digits than its factorization.

1300320003003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113199826.

The product of its (nonzero) digits is 162, while the sum is 15.

Adding to 1300320003003 its reverse (3003000230031), we get a palindrome (4303320233034).

The spelling of 1300320003003 in words is "one trillion, three hundred billion, three hundred twenty million, three thousand, three".

Divisors: 1 3 7 21 547 1641 3829 11487 113199269 339597807 792394883 2377184649 61920000143 185760000429 433440001001 1300320003003