130032000310001 has 4 divisors (see below), whose sum is σ = 130056138425712. Its totient is φ = 130007862194292.

The previous prime is 130032000309977. The next prime is 130032000310021. The reversal of 130032000310001 is 100013000230031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130032000310001 - 2¹⁴ = 130032000293617 is a prime.

It is a super-2 number, since 2×130032000310001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130032000310021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12069049775 + ... + 12069060548.

It is an arithmetic number, because the mean of its divisors is an integer number (32514034606428).

Almost surely, 2^{130032000310001} is an apocalyptic number.

It is an amenable number.

130032000310001 is a deficient number, since it is larger than the sum of its proper divisors (24138115711).

130032000310001 is an equidigital number, since it uses as much as digits as its factorization.

130032000310001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24138115710.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 130032000310001 its reverse (100013000230031), we get a palindrome (230045000540032).

The spelling of 130032000310001 in words is "one hundred thirty trillion, thirty-two billion, three hundred ten thousand, one".