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130032003131 = 373514378463
BaseRepresentation
bin111100100011010000…
…0101110100000111011
3110102122011011011122222
41321012200232200323
54112301143100011
6135422541034255
712252212534642
oct1710640564073
9412564134588
10130032003131
11501677485a8
122124b55598b
13c3536cb4b4
14641783a359
1535b0a85ddb
hex1e4682e83b

130032003131 has 4 divisors (see below), whose sum is σ = 133546381632. Its totient is φ = 126517624632.

The previous prime is 130032003091. The next prime is 130032003221. The reversal of 130032003131 is 131300230031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032003131 is a prime.

It is a super-2 number, since 2×1300320031312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130032008131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1757189195 + ... + 1757189268.

It is an arithmetic number, because the mean of its divisors is an integer number (33386595408).

Almost surely, 2130032003131 is an apocalyptic number.

130032003131 is a deficient number, since it is larger than the sum of its proper divisors (3514378501).

130032003131 is an equidigital number, since it uses as much as digits as its factorization.

130032003131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3514378500.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 130032003131 its reverse (131300230031), we get a palindrome (261332233162).

The spelling of 130032003131 in words is "one hundred thirty billion, thirty-two million, three thousand, one hundred thirty-one".

Divisors: 1 37 3514378463 130032003131