1300320102121 has 4 divisors (see below), whose sum is σ = 1300415078212. Its totient is φ = 1300225126032.

The previous prime is 1300320102049. The next prime is 1300320102149. The reversal of 1300320102121 is 1212010230031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1100528981721 + 199791120400 = 1049061^2 + 446980^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300320102121 - 2²¹ = 1300318004969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300320102095 and 1300320102104.

It is not an unprimeable number, because it can be changed into a prime (1300320102161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47467506 + ... + 47494891.

It is an arithmetic number, because the mean of its divisors is an integer number (325103769553).

Almost surely, 2^{1300320102121} is an apocalyptic number.

It is an amenable number.

1300320102121 is a deficient number, since it is larger than the sum of its proper divisors (94976091).

1300320102121 is an equidigital number, since it uses as much as digits as its factorization.

1300320102121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94976090.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1300320102121 its reverse (1212010230031), we get a palindrome (2512330332152).

The spelling of 1300320102121 in words is "one trillion, three hundred billion, three hundred twenty million, one hundred two thousand, one hundred twenty-one".