Base | Representation |
---|---|
bin | 1011110100111000101100… |
… | …1111100010101011010011 |
3 | 1201001002112111211200110001 |
4 | 2331032023033202223103 |
5 | 3201021024220042321 |
6 | 43353331044550431 |
7 | 2511310320166453 |
oct | 275161317425323 |
9 | 51032474750401 |
10 | 13003202112211 |
11 | 4163699666023 |
12 | 15601360b2417 |
13 | 7342731b647c |
14 | 32d5033ddd63 |
15 | 17839a850c91 |
hex | bd38b3e2ad3 |
13003202112211 has 4 divisors (see below), whose sum is σ = 13004509108000. Its totient is φ = 13001895116424.
The previous prime is 13003202112157. The next prime is 13003202112217. The reversal of 13003202112211 is 11221120230031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13003202112211 - 225 = 13003168557779 is a prime.
It is a super-2 number, since 2×130032021122112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13003202112217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 653482971 + ... + 653502868.
It is an arithmetic number, because the mean of its divisors is an integer number (3251127277000).
Almost surely, 213003202112211 is an apocalyptic number.
13003202112211 is a deficient number, since it is larger than the sum of its proper divisors (1306995789).
13003202112211 is an equidigital number, since it uses as much as digits as its factorization.
13003202112211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1306995788.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13003202112211 its reverse (11221120230031), we get a palindrome (24224322342242).
The spelling of 13003202112211 in words is "thirteen trillion, three billion, two hundred two million, one hundred twelve thousand, two hundred eleven".
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