Base | Representation |
---|---|
bin | 11101100100001101110110… |
… | …011100010110111110000011 |
3 | 122001101221122011021120210211 |
4 | 131210031312130112332003 |
5 | 114020421241220011003 |
6 | 1140315533204334551 |
7 | 36250340126365522 |
oct | 3544156634267603 |
9 | 561357564246724 |
10 | 130032122032003 |
11 | 38483349a58314 |
12 | 1270111a6a4457 |
13 | 5772c90480409 |
14 | 241783438a4b9 |
15 | 100767963c96d |
hex | 764376716f83 |
130032122032003 has 4 divisors (see below), whose sum is σ = 130133000328120. Its totient is φ = 129931243735888.
The previous prime is 130032122031989. The next prime is 130032122032027. The reversal of 130032122032003 is 300230221230031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130032122032003 - 241 = 127833098776451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130032122032903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50439146125 + ... + 50439148702.
It is an arithmetic number, because the mean of its divisors is an integer number (32533250082030).
Almost surely, 2130032122032003 is an apocalyptic number.
130032122032003 is a deficient number, since it is larger than the sum of its proper divisors (100878296117).
130032122032003 is a wasteful number, since it uses less digits than its factorization.
130032122032003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100878296116.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 130032122032003 its reverse (300230221230031), we get a palindrome (430262343262034).
The spelling of 130032122032003 in words is "one hundred thirty trillion, thirty-two billion, one hundred twenty-two million, thirty-two thousand, three".
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