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13003324013201 = 196831002028513
BaseRepresentation
bin1011110100111001001010…
…0000100011101010010001
31201001002212000012220011112
42331032102200203222101
53201021301421410301
643353351121423105
72511313330266104
oct275162240435221
951032760186145
1013003324013201
114163751456045
12156016aa9aa95
13734292527732
1432d51569273b
151783a63ce9bb
hexbd392823a91

13003324013201 has 8 divisors (see below), whose sum is σ = 13707750071520. Its totient is φ = 12300902013312.

The previous prime is 13003324013089. The next prime is 13003324013263. The reversal of 13003324013201 is 10231042330031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13003324013201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13003324012201) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 501001280 + ... + 501027233.

It is an arithmetic number, because the mean of its divisors is an integer number (1713468758940).

Almost surely, 213003324013201 is an apocalyptic number.

It is an amenable number.

13003324013201 is a deficient number, since it is larger than the sum of its proper divisors (704426058319).

13003324013201 is a wasteful number, since it uses less digits than its factorization.

13003324013201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1002029215.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13003324013201 its reverse (10231042330031), we get a palindrome (23234366343232).

The spelling of 13003324013201 in words is "thirteen trillion, three billion, three hundred twenty-four million, thirteen thousand, two hundred one".

Divisors: 1 19 683 12977 1002028513 19038541747 684385474379 13003324013201