Base | Representation |
---|---|
bin | 111100100011010011… |
… | …0000110011100101001 |
3 | 110102122020210202002220 |
4 | 1321012212012130221 |
5 | 4112302023140011 |
6 | 135423031144253 |
7 | 12252230523042 |
oct | 1710646063451 |
9 | 412566722086 |
10 | 130033411881 |
11 | 5016851aa5a |
12 | 2124bb15089 |
13 | c353aa2789 |
14 | 6417ac58c9 |
15 | 35b0c63506 |
hex | 1e46986729 |
130033411881 has 4 divisors (see below), whose sum is σ = 173377882512. Its totient is φ = 86688941252.
The previous prime is 130033411861. The next prime is 130033411901. The reversal of 130033411881 is 188114330031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (130033411861) and next prime (130033411901).
It is a cyclic number.
It is not a de Polignac number, because 130033411881 - 214 = 130033395497 is a prime.
It is a super-2 number, since 2×1300334118812 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130033411861) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21672235311 + ... + 21672235316.
It is an arithmetic number, because the mean of its divisors is an integer number (43344470628).
Almost surely, 2130033411881 is an apocalyptic number.
It is an amenable number.
130033411881 is a deficient number, since it is larger than the sum of its proper divisors (43344470631).
130033411881 is an equidigital number, since it uses as much as digits as its factorization.
130033411881 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43344470630.
The product of its (nonzero) digits is 6912, while the sum is 33.
The spelling of 130033411881 in words is "one hundred thirty billion, thirty-three million, four hundred eleven thousand, eight hundred eighty-one".
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