Base | Representation |
---|---|
bin | 11000001110001000… |
… | …01111101111011011 |
3 | 1020120020021222110011 |
4 | 30013010033233123 |
5 | 203112341033301 |
6 | 5550153102351 |
7 | 640144355560 |
oct | 140704175733 |
9 | 36506258404 |
10 | 13003455451 |
11 | 55731255a8 |
12 | 262a9b79b7 |
13 | 12c301174c |
14 | 8b4dc8867 |
15 | 5118d5a51 |
hex | 30710fbdb |
13003455451 has 16 divisors (see below), whose sum is σ = 15110774784. Its totient is φ = 10960113024.
The previous prime is 13003455433. The next prime is 13003455541. The reversal of 13003455451 is 15455430031.
It is not a de Polignac number, because 13003455451 - 25 = 13003455419 is a prime.
It is a super-2 number, since 2×130034554512 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13003455151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35736 + ... + 165178.
It is an arithmetic number, because the mean of its divisors is an integer number (944423424).
Almost surely, 213003455451 is an apocalyptic number.
13003455451 is a deficient number, since it is larger than the sum of its proper divisors (2107319333).
13003455451 is a wasteful number, since it uses less digits than its factorization.
13003455451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 129690.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 13003455451 its reverse (15455430031), we get a palindrome (28458885482).
The spelling of 13003455451 in words is "thirteen billion, three million, four hundred fifty-five thousand, four hundred fifty-one".
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