Base | Representation |
---|---|
bin | 111100100011010110… |
… | …0001101110101111011 |
3 | 110102122100211012012222 |
4 | 1321012230031311323 |
5 | 4112302430440120 |
6 | 135423125354255 |
7 | 12252250251002 |
oct | 1710654156573 |
9 | 412570735188 |
10 | 130035015035 |
11 | 50169415482 |
12 | 2125056898b |
13 | c3542143a3 |
14 | 6417dc1c39 |
15 | 35b0e7d525 |
hex | 1e46b0dd7b |
130035015035 has 8 divisors (see below), whose sum is σ = 158239793376. Its totient is φ = 102562828480.
The previous prime is 130035015017. The next prime is 130035015043. The reversal of 130035015035 is 530510530031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130035015035 - 28 = 130035014779 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130035014995 and 130035015013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 183147554 + ... + 183148263.
It is an arithmetic number, because the mean of its divisors is an integer number (19779974172).
Almost surely, 2130035015035 is an apocalyptic number.
130035015035 is a deficient number, since it is larger than the sum of its proper divisors (28204778341).
130035015035 is an equidigital number, since it uses as much as digits as its factorization.
130035015035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 366295893.
The product of its (nonzero) digits is 3375, while the sum is 26.
Adding to 130035015035 its reverse (530510530031), we get a palindrome (660545545066).
The spelling of 130035015035 in words is "one hundred thirty billion, thirty-five million, fifteen thousand, thirty-five".
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