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130038355 = 5171529863
BaseRepresentation
bin1111100000000…
…11101001010011
3100001200122002101
413300003221103
5231242211410
620523101231
73136210366
oct760035123
9301618071
10130038355
1167448817
1237671817
1320c30095
14133b00dd
15b639d3a
hex7c03a53

130038355 has 8 divisors (see below), whose sum is σ = 165225312. Its totient is φ = 97911168.

The previous prime is 130038353. The next prime is 130038361. The reversal of 130038355 is 553830031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130038355 - 21 = 130038353 is a prime.

It is a super-2 number, since 2×1300383552 = 33819947542212050, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130038353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 764847 + ... + 765016.

It is an arithmetic number, because the mean of its divisors is an integer number (20653164).

Almost surely, 2130038355 is an apocalyptic number.

130038355 is a deficient number, since it is larger than the sum of its proper divisors (35186957).

130038355 is a wasteful number, since it uses less digits than its factorization.

130038355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1529885.

The product of its (nonzero) digits is 5400, while the sum is 28.

The square root of 130038355 is about 11403.4361049642. The cubic root of 130038355 is about 506.6295171766.

Adding to 130038355 its reverse (553830031), we get a palindrome (683868386).

The spelling of 130038355 in words is "one hundred thirty million, thirty-eight thousand, three hundred fifty-five".

Divisors: 1 5 17 85 1529863 7649315 26007671 130038355