Base | Representation |
---|---|
bin | 11000001110001100… |
… | …10100110010010011 |
3 | 1020120021022122222120 |
4 | 30013012110302103 |
5 | 203113011003103 |
6 | 5550212505323 |
7 | 640152115422 |
oct | 140706246223 |
9 | 36507278876 |
10 | 13004000403 |
11 | 5573467a79 |
12 | 262b01b243 |
13 | 12c31727c4 |
14 | 8b50cb2b9 |
15 | 511992253 |
hex | 307194c93 |
13004000403 has 16 divisors (see below), whose sum is σ = 17963767200. Its totient is φ = 8357690880.
The previous prime is 13004000333. The next prime is 13004000419. The reversal of 13004000403 is 30400040031.
It is not a de Polignac number, because 13004000403 - 28 = 13004000147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13004000473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55558 + ... + 170571.
It is an arithmetic number, because the mean of its divisors is an integer number (1122735450).
Almost surely, 213004000403 is an apocalyptic number.
13004000403 is a deficient number, since it is larger than the sum of its proper divisors (4959766797).
13004000403 is a wasteful number, since it uses less digits than its factorization.
13004000403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 226822.
The product of its (nonzero) digits is 144, while the sum is 15.
Adding to 13004000403 its reverse (30400040031), we get a palindrome (43404040434).
The spelling of 13004000403 in words is "thirteen billion, four million, four hundred three", and thus it is an aban number.
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