1300401044441 has 4 divisors (see below), whose sum is σ = 1300624448484. Its totient is φ = 1300177640400.

The previous prime is 1300401044419. The next prime is 1300401044519. The reversal of 1300401044441 is 1444401040031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 951787555216 + 348613489225 = 975596^2 + 590435^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300401044441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300401044441.

It is not an unprimeable number, because it can be changed into a prime (1300401044141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111693290 + ... + 111704931.

It is an arithmetic number, because the mean of its divisors is an integer number (325156112121).

Almost surely, 2^{1300401044441} is an apocalyptic number.

It is an amenable number.

1300401044441 is a deficient number, since it is larger than the sum of its proper divisors (223404043).

1300401044441 is an equidigital number, since it uses as much as digits as its factorization.

1300401044441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 223404042.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1300401044441 its reverse (1444401040031), we get a palindrome (2744802084472).

The spelling of 1300401044441 in words is "one trillion, three hundred billion, four hundred one million, forty-four thousand, four hundred forty-one".