130040364435 has 16 divisors (see below), whose sum is σ = 208561167360. Its totient is φ = 69189332960.

The previous prime is 130040364431. The next prime is 130040364437. The reversal of 130040364435 is 534463040031.

It is not a de Polignac number, because 130040364435 - 2² = 130040364431 is a prime.

It is a super-2 number, since 2×130040364435² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130040364396 and 130040364405.

It is not an unprimeable number, because it can be changed into a prime (130040364431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10339011 + ... + 10351580.

It is an arithmetic number, because the mean of its divisors is an integer number (13035072960).

Almost surely, 2^130040364435 is an apocalyptic number.

130040364435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

130040364435 is a deficient number, since it is larger than the sum of its proper divisors (78520802925).

130040364435 is a wasteful number, since it uses less digits than its factorization.

130040364435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20691018.

The product of its (nonzero) digits is 51840, while the sum is 33.

The spelling of 130040364435 in words is "one hundred thirty billion, forty million, three hundred sixty-four thousand, four hundred thirty-five".