130040555 has 8 divisors (see below), whose sum is σ = 156114000. Its totient is φ = 103988896.

The previous prime is 130040539. The next prime is 130040563. The reversal of 130040555 is 555040031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130040555 - 2⁴ = 130040539 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130040555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14021 + ... + 21369.

It is an arithmetic number, because the mean of its divisors is an integer number (19514250).

Almost surely, 2^130040555 is an apocalyptic number.

130040555 is a deficient number, since it is larger than the sum of its proper divisors (26073445).

130040555 is an equidigital number, since it uses as much as digits as its factorization.

130040555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10893.

The product of its (nonzero) digits is 1500, while the sum is 23.

The square root of 130040555 is about 11403.5325667093. The cubic root of 130040555 is about 506.6323742276.

Adding to 130040555 its reverse (555040031), we get a palindrome (685080586).

The spelling of 130040555 in words is "one hundred thirty million, forty thousand, five hundred fifty-five".