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1300412345 = 51929472019
BaseRepresentation
bin100110110000010…
…1011011110111001
310100121221210101012
41031200223132321
510130401143340
6333012203305
744140215431
oct11540533671
93317853335
101300412345
1160805a051
12303609535
1317955087b
14c49cb2c1
1579272565
hex4d82b7b9

1300412345 has 16 divisors (see below), whose sum is σ = 1699272000. Its totient is φ = 951588288.

The previous prime is 1300412339. The next prime is 1300412359. The reversal of 1300412345 is 5432140031.

It is a cyclic number.

It is not a de Polignac number, because 1300412345 - 24 = 1300412329 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1300412345.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 233255 + ... + 238764.

It is an arithmetic number, because the mean of its divisors is an integer number (106204500).

Almost surely, 21300412345 is an apocalyptic number.

It is an amenable number.

1300412345 is a deficient number, since it is larger than the sum of its proper divisors (398859655).

1300412345 is a wasteful number, since it uses less digits than its factorization.

1300412345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 472072.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 1300412345 is about 36061.2304975856. The cubic root of 1300412345 is about 1091.5082632727.

Adding to 1300412345 its reverse (5432140031), we get a palindrome (6732552376).

The spelling of 1300412345 in words is "one billion, three hundred million, four hundred twelve thousand, three hundred forty-five".

Divisors: 1 5 19 29 95 145 551 2755 472019 2360095 8968361 13688551 44841805 68442755 260082469 1300412345