1300412540849 has 4 divisors (see below), whose sum is σ = 1302689971440. Its totient is φ = 1298135110260.

The previous prime is 1300412540771. The next prime is 1300412540873. The reversal of 1300412540849 is 9480452140031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300412540849 - 2³⁶ = 1231693064113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300472540849) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1138714439 + ... + 1138715580.

It is an arithmetic number, because the mean of its divisors is an integer number (325672492860).

Almost surely, 2^{1300412540849} is an apocalyptic number.

It is an amenable number.

1300412540849 is a deficient number, since it is larger than the sum of its proper divisors (2277430591).

1300412540849 is an equidigital number, since it uses as much as digits as its factorization.

1300412540849 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2277430590.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 1300412540849 in words is "one trillion, three hundred billion, four hundred twelve million, five hundred forty thousand, eight hundred forty-nine".