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13004140105 = 511236438911
BaseRepresentation
bin11000001110001101…
…10110111001001001
31020120021120202121201
430013012312321021
5203113024440410
65550215504201
7640153236625
oct140706667111
936507522551
1013004140105
115573552a30
12262b088061
1312c31c1278
148b5126185
155119bd83a
hex3071b6e49

13004140105 has 8 divisors (see below), whose sum is σ = 17023601664. Its totient is φ = 9457556400.

The previous prime is 13004140043. The next prime is 13004140117. The reversal of 13004140105 is 50104140031.

13004140105 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13004140105 - 27 = 13004139977 is a prime.

It is a super-2 number, since 2×130041401052 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118219401 + ... + 118219510.

It is an arithmetic number, because the mean of its divisors is an integer number (2127950208).

Almost surely, 213004140105 is an apocalyptic number.

It is an amenable number.

13004140105 is a deficient number, since it is larger than the sum of its proper divisors (4019461559).

13004140105 is a wasteful number, since it uses less digits than its factorization.

13004140105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236438927.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 13004140105 its reverse (50104140031), we get a palindrome (63108280136).

The spelling of 13004140105 in words is "thirteen billion, four million, one hundred forty thousand, one hundred five".

Divisors: 1 5 11 55 236438911 1182194555 2600828021 13004140105