1300424101121 has 4 divisors (see below), whose sum is σ = 1300441340352. Its totient is φ = 1300406861892.

The previous prime is 1300424101057. The next prime is 1300424101127. The reversal of 1300424101121 is 1211014240031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300424101121 - 2⁶ = 1300424101057 is a prime.

It is a super-2 number, since 2×1300424101121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300424101093 and 1300424101102.

It is not an unprimeable number, because it can be changed into a prime (1300424101127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8505965 + ... + 8657498.

It is an arithmetic number, because the mean of its divisors is an integer number (325110335088).

Almost surely, 2^{1300424101121} is an apocalyptic number.

It is an amenable number.

1300424101121 is a deficient number, since it is larger than the sum of its proper divisors (17239231).

1300424101121 is an equidigital number, since it uses as much as digits as its factorization.

1300424101121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17239230.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1300424101121 its reverse (1211014240031), we get a palindrome (2511438341152).

The spelling of 1300424101121 in words is "one trillion, three hundred billion, four hundred twenty-four million, one hundred one thousand, one hundred twenty-one".