Base | Representation |
---|---|
bin | 11000001110001110… |
… | …11110110011000011 |
3 | 1020120021220001211102 |
4 | 30013013132303003 |
5 | 203113100203210 |
6 | 5550223205015 |
7 | 640154520305 |
oct | 140707366303 |
9 | 36507801742 |
10 | 13004303555 |
11 | 5573654811 |
12 | 262b14676b |
13 | 12c324a799 |
14 | 8b5169975 |
15 | 511a01ea5 |
hex | 3071decc3 |
13004303555 has 16 divisors (see below), whose sum is σ = 15831163584. Its totient is φ = 10252892160.
The previous prime is 13004303479. The next prime is 13004303567. The reversal of 13004303555 is 55530340031.
It is a de Polignac number, because none of the positive numbers 2k-13004303555 is a prime.
It is a super-2 number, since 2×130043035552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1170587 + ... + 1181643.
It is an arithmetic number, because the mean of its divisors is an integer number (989447724).
Almost surely, 213004303555 is an apocalyptic number.
13004303555 is a deficient number, since it is larger than the sum of its proper divisors (2826860029).
13004303555 is a wasteful number, since it uses less digits than its factorization.
13004303555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14446.
The product of its (nonzero) digits is 13500, while the sum is 29.
Adding to 13004303555 its reverse (55530340031), we get a palindrome (68534643586).
The spelling of 13004303555 in words is "thirteen billion, four million, three hundred three thousand, five hundred fifty-five".
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