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1300434035 = 5318389897
BaseRepresentation
bin100110110000011…
…0000110001110011
310100121222220010112
41031200300301303
510130402342120
6333012451535
744140335605
oct11540606163
93317886115
101300434035
1160807437a
12303619bab
1317955a6c4
14c49d5175
1579278bc5
hex4d830c73

1300434035 has 8 divisors (see below), whose sum is σ = 1610860416. Its totient is φ = 1006787520.

The previous prime is 1300434029. The next prime is 1300434071. The reversal of 1300434035 is 5304340031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1300434035 - 28 = 1300433779 is a prime.

It is a super-2 number, since 2×13004340352 = 3382257358772762450, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300434035.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4194794 + ... + 4195103.

It is an arithmetic number, because the mean of its divisors is an integer number (201357552).

Almost surely, 21300434035 is an apocalyptic number.

1300434035 is a deficient number, since it is larger than the sum of its proper divisors (310426381).

1300434035 is an equidigital number, since it uses as much as digits as its factorization.

1300434035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8389933.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 1300434035 is about 36061.5312348214. The cubic root of 1300434035 is about 1091.5143317793.

Adding to 1300434035 its reverse (5304340031), we get a palindrome (6604774066).

The spelling of 1300434035 in words is "one billion, three hundred million, four hundred thirty-four thousand, thirty-five".

Divisors: 1 5 31 155 8389897 41949485 260086807 1300434035