13004354531 has 8 divisors (see below), whose sum is σ = 14878298880. Its totient is φ = 11134455048.

The previous prime is 13004354513. The next prime is 13004354563. The reversal of 13004354531 is 13545340031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13004354531 - 2¹⁴ = 13004338147 is a prime.

It is a super-2 number, since 2×13004354531² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13004354494 and 13004354503.

It is not an unprimeable number, because it can be changed into a prime (13004354581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1004321 + ... + 1017186.

It is an arithmetic number, because the mean of its divisors is an integer number (1859787360).

Almost surely, 2^13004354531 is an apocalyptic number.

13004354531 is a deficient number, since it is larger than the sum of its proper divisors (1873944349).

13004354531 is an equidigital number, since it uses as much as digits as its factorization.

13004354531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2022433.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 13004354531 its reverse (13545340031), we get a palindrome (26549694562).

The spelling of 13004354531 in words is "thirteen billion, four million, three hundred fifty-four thousand, five hundred thirty-one".