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130043720123 = 433024272561
BaseRepresentation
bin111100100011100110…
…1011011000110111011
3110102122222012110100122
41321013031123012323
54112312143020443
6135424040123455
712252414245162
oct1710715330673
9412588173318
10130043720123
1150173320769
122125346658b
13c355c71725
14641920a3d9
1535b1aec968
hex1e4735b1bb

130043720123 has 4 divisors (see below), whose sum is σ = 133067992728. Its totient is φ = 127019447520.

The previous prime is 130043720113. The next prime is 130043720129. The reversal of 130043720123 is 321027340031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 321027340031 = 1933571660283.

It is not a de Polignac number, because 130043720123 - 232 = 125748752827 is a prime.

It is a super-2 number, since 2×1300437201232 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130043720092 and 130043720101.

It is not an unprimeable number, because it can be changed into a prime (130043720129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1512136238 + ... + 1512136323.

It is an arithmetic number, because the mean of its divisors is an integer number (33266998182).

Almost surely, 2130043720123 is an apocalyptic number.

130043720123 is a deficient number, since it is larger than the sum of its proper divisors (3024272605).

130043720123 is an equidigital number, since it uses as much as digits as its factorization.

130043720123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3024272604.

The product of its (nonzero) digits is 3024, while the sum is 26.

The spelling of 130043720123 in words is "one hundred thirty billion, forty-three million, seven hundred twenty thousand, one hundred twenty-three".

Divisors: 1 43 3024272561 130043720123