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130044011043 = 362876894863
BaseRepresentation
bin111100100011100111…
…0100010001000100011
3110102122222202020102110
41321013032202020203
54112312231323133
6135424050250403
712252416566302
oct1710716421043
9412588666373
10130044011043
11501734aa2a1
1221253586a03
13c356043c7b
146419284439
1535b1b58c63
hex1e473a2223

130044011043 has 8 divisors (see below), whose sum is σ = 173419619328. Its totient is φ = 86682205064.

The previous prime is 130044011033. The next prime is 130044011077. The reversal of 130044011043 is 340110440031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130044011043 - 212 = 130044006947 is a prime.

It is a super-2 number, since 2×1300440110432 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130044011033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3428571 + ... + 3466292.

It is an arithmetic number, because the mean of its divisors is an integer number (21677452416).

Almost surely, 2130044011043 is an apocalyptic number.

130044011043 is a deficient number, since it is larger than the sum of its proper divisors (43375608285).

130044011043 is an equidigital number, since it uses as much as digits as its factorization.

130044011043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6901153.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 130044011043 its reverse (340110440031), we get a palindrome (470154451074).

The spelling of 130044011043 in words is "one hundred thirty billion, forty-four million, eleven thousand, forty-three".

Divisors: 1 3 6287 18861 6894863 20684589 43348003681 130044011043