Base | Representation |
---|---|
bin | 111100100011100111… |
… | …0101001011111111011 |
3 | 110102122222210202210210 |
4 | 1321013032221133323 |
5 | 4112312233304321 |
6 | 135424051042203 |
7 | 12252420053250 |
oct | 1710716513773 |
9 | 412588722723 |
10 | 130044041211 |
11 | 5017351aa27 |
12 | 212535a0363 |
13 | c356054916 |
14 | 6419291427 |
15 | 35b1b62b76 |
hex | 1e473a97fb |
130044041211 has 16 divisors (see below), whose sum is σ = 209818957824. Its totient is φ = 69939652224.
The previous prime is 130044041189. The next prime is 130044041249. The reversal of 130044041211 is 112140440031.
It is not a de Polignac number, because 130044041211 - 210 = 130044040187 is a prime.
It is a super-2 number, since 2×1300440412112 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (130044041261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182134155 + ... + 182134868.
It is an arithmetic number, because the mean of its divisors is an integer number (13113684864).
Almost surely, 2130044041211 is an apocalyptic number.
130044041211 is a deficient number, since it is larger than the sum of its proper divisors (79774916613).
130044041211 is a wasteful number, since it uses less digits than its factorization.
130044041211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364269050.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 130044041211 its reverse (112140440031), we get a palindrome (242184481242).
The spelling of 130044041211 in words is "one hundred thirty billion, forty-four million, forty-one thousand, two hundred eleven".
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