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130044041211 = 3717364269023
BaseRepresentation
bin111100100011100111…
…0101001011111111011
3110102122222210202210210
41321013032221133323
54112312233304321
6135424051042203
712252420053250
oct1710716513773
9412588722723
10130044041211
115017351aa27
12212535a0363
13c356054916
146419291427
1535b1b62b76
hex1e473a97fb

130044041211 has 16 divisors (see below), whose sum is σ = 209818957824. Its totient is φ = 69939652224.

The previous prime is 130044041189. The next prime is 130044041249. The reversal of 130044041211 is 112140440031.

It is not a de Polignac number, because 130044041211 - 210 = 130044040187 is a prime.

It is a super-2 number, since 2×1300440412112 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is not an unprimeable number, because it can be changed into a prime (130044041261) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182134155 + ... + 182134868.

It is an arithmetic number, because the mean of its divisors is an integer number (13113684864).

Almost surely, 2130044041211 is an apocalyptic number.

130044041211 is a deficient number, since it is larger than the sum of its proper divisors (79774916613).

130044041211 is a wasteful number, since it uses less digits than its factorization.

130044041211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 364269050.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 130044041211 its reverse (112140440031), we get a palindrome (242184481242).

The spelling of 130044041211 in words is "one hundred thirty billion, forty-four million, forty-one thousand, two hundred eleven".

Divisors: 1 3 7 17 21 51 119 357 364269023 1092807069 2549883161 6192573391 7649649483 18577720173 43348013737 130044041211