Base | Representation |
---|---|
bin | 111100100011100111… |
… | …1010110011110011011 |
3 | 110102200000011010111220 |
4 | 1321013033112132123 |
5 | 4112312310203220 |
6 | 135424055023123 |
7 | 12252421451325 |
oct | 1710717263633 |
9 | 412600133456 |
10 | 130044225435 |
11 | 50173636383 |
12 | 2125366aaa3 |
13 | c3560ba727 |
14 | 64192dc615 |
15 | 35b1b9c540 |
hex | 1e473d679b |
130044225435 has 16 divisors (see below), whose sum is σ = 208099242240. Its totient is φ = 69347426400.
The previous prime is 130044225427. The next prime is 130044225517. The reversal of 130044225435 is 534522440031.
It is not a de Polignac number, because 130044225435 - 23 = 130044225427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130044225396 and 130044225405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479425 + ... + 699954.
It is an arithmetic number, because the mean of its divisors is an integer number (13006202640).
Almost surely, 2130044225435 is an apocalyptic number.
130044225435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
130044225435 is a deficient number, since it is larger than the sum of its proper divisors (78055016805).
130044225435 is a wasteful number, since it uses less digits than its factorization.
130044225435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1186738.
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 130044225435 its reverse (534522440031), we get a palindrome (664566665466).
The spelling of 130044225435 in words is "one hundred thirty billion, forty-four million, two hundred twenty-five thousand, four hundred thirty-five".
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