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130051112531 = 17232129156229
BaseRepresentation
bin111100100011110100…
…1100111111001010011
3110102200111010000211112
41321013221213321103
54112321041100111
6135424502403535
712252534134324
oct1710751477123
9412614100745
10130051112531
115017750a79a
1221255a305ab
13c35765c432
14641a1b244b
1535b25ace8b
hex1e47a67e53

130051112531 has 16 divisors (see below), whose sum is σ = 143756596800. Its totient is φ = 117023520768.

The previous prime is 130051112501. The next prime is 130051112647. The reversal of 130051112531 is 135211150031.

It is a cyclic number.

It is not a de Polignac number, because 130051112531 - 210 = 130051111507 is a prime.

It is a super-2 number, since 2×1300511125312 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a junction number, because it is equal to n+sod(n) for n = 130051112497 and 130051112506.

It is not an unprimeable number, because it can be changed into a prime (130051112501) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 754325 + ... + 910553.

It is an arithmetic number, because the mean of its divisors is an integer number (8984787300).

Almost surely, 2130051112531 is an apocalyptic number.

130051112531 is a deficient number, since it is larger than the sum of its proper divisors (13705484269).

130051112531 is a wasteful number, since it uses less digits than its factorization.

130051112531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158398.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 130051112531 its reverse (135211150031), we get a palindrome (265262262562).

The spelling of 130051112531 in words is "one hundred thirty billion, fifty-one million, one hundred twelve thousand, five hundred thirty-one".

Divisors: 1 17 23 391 2129 36193 48967 156229 832439 2655893 3593267 61085539 332611541 5654396197 7650065443 130051112531