13005323513545 has 16 divisors (see below), whose sum is σ = 17765374730112. Its totient is φ = 9047181573760.

The previous prime is 13005323513537. The next prime is 13005323513563. The reversal of 13005323513545 is 54531532350031.

It is not a de Polignac number, because 13005323513545 - 2³ = 13005323513537 is a prime.

It is a super-3 number, since 3×13005323513545³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13005323513498 and 13005323513507.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5140442812 + ... + 5140445341.

It is an arithmetic number, because the mean of its divisors is an integer number (1110335920632).

Almost surely, 2^{13005323513545} is an apocalyptic number.

It is an amenable number.

13005323513545 is a deficient number, since it is larger than the sum of its proper divisors (4760051216567).

13005323513545 is a wasteful number, since it uses less digits than its factorization.

13005323513545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10280888192.

The product of its (nonzero) digits is 405000, while the sum is 40.

Adding to 13005323513545 its reverse (54531532350031), we get a palindrome (67536855863576).

The spelling of 13005323513545 in words is "thirteen trillion, five billion, three hundred twenty-three million, five hundred thirteen thousand, five hundred forty-five".