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130053241403 = 211616366073
BaseRepresentation
bin111100100011111000…
…1101111101000111011
3110102200122010012002122
41321013301233220323
54112322112211103
6135425020151455
712252561212051
oct1710761575073
9412618105078
10130053241403
1150178734198
122125669858b
13c357c26417
14641a5a81d1
1535b287db38
hex1e47c6fa3b

130053241403 has 4 divisors (see below), whose sum is σ = 130669607688. Its totient is φ = 129436875120.

The previous prime is 130053241397. The next prime is 130053241463. The reversal of 130053241403 is 304142350031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130053241403 - 228 = 129784805947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130053241463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308182826 + ... + 308183247.

It is an arithmetic number, because the mean of its divisors is an integer number (32667401922).

Almost surely, 2130053241403 is an apocalyptic number.

130053241403 is a deficient number, since it is larger than the sum of its proper divisors (616366285).

130053241403 is an equidigital number, since it uses as much as digits as its factorization.

130053241403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 616366284.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 130053241403 its reverse (304142350031), we get a palindrome (434195591434).

The spelling of 130053241403 in words is "one hundred thirty billion, fifty-three million, two hundred forty-one thousand, four hundred three".

Divisors: 1 211 616366073 130053241403