130064423205403 has 4 divisors (see below), whose sum is σ = 134260049760448. Its totient is φ = 125868796650360.

The previous prime is 130064423205349. The next prime is 130064423205461. The reversal of 130064423205403 is 304502324460031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130064423205403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130064423205463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2097813277476 + ... + 2097813277537.

It is an arithmetic number, because the mean of its divisors is an integer number (33565012440112).

Almost surely, 2^{130064423205403} is an apocalyptic number.

130064423205403 is a deficient number, since it is larger than the sum of its proper divisors (4195626555045).

130064423205403 is an equidigital number, since it uses as much as digits as its factorization.

130064423205403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4195626555044.

The product of its (nonzero) digits is 207360, while the sum is 37.

Adding to 130064423205403 its reverse (304502324460031), we get a palindrome (434566747665434).

The spelling of 130064423205403 in words is "one hundred thirty trillion, sixty-four billion, four hundred twenty-three million, two hundred five thousand, four hundred three".