Base | Representation |
---|---|
bin | 1011110101000100111001… |
… | …1111011001001101110011 |
3 | 1201001101222210200010110121 |
4 | 2331101032133121031303 |
5 | 3201044231310344013 |
6 | 43355032102511111 |
7 | 2511454434245254 |
oct | 275211637311563 |
9 | 51041883603417 |
10 | 13006477824883 |
11 | 416501a721484 |
12 | 15608ab135497 |
13 | 734675a43aaa |
14 | 32d734496b2b |
15 | 1784dd20758d |
hex | bd44e7d9373 |
13006477824883 has 4 divisors (see below), whose sum is σ = 13006502576208. Its totient is φ = 13006453073560.
The previous prime is 13006477824871. The next prime is 13006477824919. The reversal of 13006477824883 is 38842877460031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13006477824883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13006477824083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11569948 + ... + 12644233.
It is an arithmetic number, because the mean of its divisors is an integer number (3251625644052).
Almost surely, 213006477824883 is an apocalyptic number.
13006477824883 is a deficient number, since it is larger than the sum of its proper divisors (24751325).
13006477824883 is an equidigital number, since it uses as much as digits as its factorization.
13006477824883 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24751324.
The product of its (nonzero) digits is 43352064, while the sum is 61.
The spelling of 13006477824883 in words is "thirteen trillion, six billion, four hundred seventy-seven million, eight hundred twenty-four thousand, eight hundred eighty-three".
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