Base | Representation |
---|---|
bin | 111100100100101101… |
… | …0000001010111100001 |
3 | 110102202112112222110220 |
4 | 1321021122001113201 |
5 | 4112401111430433 |
6 | 135431434113253 |
7 | 12253342442463 |
oct | 1711132012741 |
9 | 412675488426 |
10 | 130080576993 |
11 | 50192104894 |
12 | 2126387b829 |
13 | c3607a7723 |
14 | 6420082133 |
15 | 35b4e7d2b3 |
hex | 1e496815e1 |
130080576993 has 4 divisors (see below), whose sum is σ = 173440769328. Its totient is φ = 86720384660.
The previous prime is 130080576949. The next prime is 130080577007. The reversal of 130080576993 is 399675080031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130080576993 - 26 = 130080576929 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130080576943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21680096163 + ... + 21680096168.
It is an arithmetic number, because the mean of its divisors is an integer number (43360192332).
Almost surely, 2130080576993 is an apocalyptic number.
It is an amenable number.
130080576993 is a deficient number, since it is larger than the sum of its proper divisors (43360192335).
130080576993 is an equidigital number, since it uses as much as digits as its factorization.
130080576993 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43360192334.
The product of its (nonzero) digits is 1224720, while the sum is 51.
The spelling of 130080576993 in words is "one hundred thirty billion, eighty million, five hundred seventy-six thousand, nine hundred ninety-three".
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