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130100321011 = 139339337567
BaseRepresentation
bin111100100101010010…
…1010101101011110011
3110102210220201002011211
41321022211111223303
54112421140233021
6135433421220551
712254002324303
oct1711245255363
9412726632154
10130100321011
11501a226a861
122126a401757
13c3648cb48b
146422941603
1535b6a7d3e1
hex1e4a955af3

130100321011 has 4 divisors (see below), whose sum is σ = 130109672512. Its totient is φ = 130090969512.

The previous prime is 130100321009. The next prime is 130100321027. The reversal of 130100321011 is 110123001031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130100321011 - 21 = 130100321009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130100320982 and 130100321000.

It is not an unprimeable number, because it can be changed into a prime (130100321051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4654851 + ... + 4682716.

It is an arithmetic number, because the mean of its divisors is an integer number (32527418128).

Almost surely, 2130100321011 is an apocalyptic number.

130100321011 is a deficient number, since it is larger than the sum of its proper divisors (9351501).

130100321011 is an equidigital number, since it uses as much as digits as its factorization.

130100321011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9351500.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 130100321011 its reverse (110123001031), we get a palindrome (240223322042).

The spelling of 130100321011 in words is "one hundred thirty billion, one hundred million, three hundred twenty-one thousand, eleven".

Divisors: 1 13933 9337567 130100321011