Base | Representation |
---|---|
bin | 10010111011101010010… |
… | …011111100011011101011 |
3 | 11121101010201010202120021 |
4 | 102323222103330123223 |
5 | 132303432333021303 |
6 | 2433402025341311 |
7 | 162665161623262 |
oct | 22735223743353 |
9 | 4541121122507 |
10 | 1301011220203 |
11 | 461834a09972 |
12 | 19018a037837 |
13 | 958b97626a6 |
14 | 46d7d9b75d9 |
15 | 23c97ac0ebd |
hex | 12eea4fc6eb |
1301011220203 has 8 divisors (see below), whose sum is σ = 1323250287840. Its totient is φ = 1278880901760.
The previous prime is 1301011220137. The next prime is 1301011220263. The reversal of 1301011220203 is 3020221101031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301011220203 is a prime.
It is a super-2 number, since 2×13010112202032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1301011220263) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27163168 + ... + 27211021.
It is an arithmetic number, because the mean of its divisors is an integer number (165406285980).
Almost surely, 21301011220203 is an apocalyptic number.
1301011220203 is a deficient number, since it is larger than the sum of its proper divisors (22239067637).
1301011220203 is an equidigital number, since it uses as much as digits as its factorization.
1301011220203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54374597.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1301011220203 its reverse (3020221101031), we get a palindrome (4321232321234).
The spelling of 1301011220203 in words is "one trillion, three hundred one billion, eleven million, two hundred twenty thousand, two hundred three".
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