13010132300041 has 4 divisors (see below), whose sum is σ = 13327452600084. Its totient is φ = 12692812000000.

The previous prime is 13010132300029. The next prime is 13010132300059. The reversal of 13010132300041 is 14000323101031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7335993918016 + 5674138382025 = 2708504^2 + 2382045^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010132300041 - 2⁹ = 13010132299529 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13010132299991 and 13010132300018.

It is not an unprimeable number, because it can be changed into a prime (13010132304041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158660149960 + ... + 158660150041.

It is an arithmetic number, because the mean of its divisors is an integer number (3331863150021).

Almost surely, 2^{13010132300041} is an apocalyptic number.

It is an amenable number.

13010132300041 is a deficient number, since it is larger than the sum of its proper divisors (317320300043).

13010132300041 is an equidigital number, since it uses as much as digits as its factorization.

13010132300041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 317320300042.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13010132300041 its reverse (14000323101031), we get a palindrome (27010455401072).

The spelling of 13010132300041 in words is "thirteen trillion, ten billion, one hundred thirty-two million, three hundred thousand, forty-one".