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13010242555 = 52602048511
BaseRepresentation
bin11000001110111100…
…01000101111111011
31020120201001210121101
430013132020233323
5203121110230210
65550554352231
7640256144212
oct140736105773
936521053541
1013010242555
115576a40882
12263112b677
1312c4549a9b
148b5c74079
155122c6a3a
hex307788bfb

13010242555 has 4 divisors (see below), whose sum is σ = 15612291072. Its totient is φ = 10408194040.

The previous prime is 13010242547. The next prime is 13010242561. The reversal of 13010242555 is 55524201031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13010242555 - 23 = 13010242547 is a prime.

It is a super-2 number, since 2×130102425552 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1301024251 + ... + 1301024260.

It is an arithmetic number, because the mean of its divisors is an integer number (3903072768).

Almost surely, 213010242555 is an apocalyptic number.

13010242555 is a deficient number, since it is larger than the sum of its proper divisors (2602048517).

13010242555 is an equidigital number, since it uses as much as digits as its factorization.

13010242555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2602048516.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 13010242555 its reverse (55524201031), we get a palindrome (68534443586).

The spelling of 13010242555 in words is "thirteen billion, ten million, two hundred forty-two thousand, five hundred fifty-five".

Divisors: 1 5 2602048511 13010242555