13010302001113 has 4 divisors (see below), whose sum is σ = 13010313180580. Its totient is φ = 13010290821648.

The previous prime is 13010302001063. The next prime is 13010302001117. The reversal of 13010302001113 is 31110020301031.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1342940275609 + 11667361725504 = 1158853^2 + 3415752^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13010302001113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13010302001117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3610470 + ... + 6249487.

It is an arithmetic number, because the mean of its divisors is an integer number (3252578295145).

Almost surely, 2^{13010302001113} is an apocalyptic number.

It is an amenable number.

13010302001113 is a deficient number, since it is larger than the sum of its proper divisors (11179467).

13010302001113 is an equidigital number, since it uses as much as digits as its factorization.

13010302001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11179466.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13010302001113 its reverse (31110020301031), we get a palindrome (44120322302144).

The spelling of 13010302001113 in words is "thirteen trillion, ten billion, three hundred two million, one thousand, one hundred thirteen".