13010434131 has 4 divisors (see below), whose sum is σ = 17347245512. Its totient is φ = 8673622752.

The previous prime is 13010434123. The next prime is 13010434133. The reversal of 13010434131 is 13143401031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13010434131 - 2³ = 13010434123 is a prime.

It is a super-2 number, since 2×13010434131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13010434098 and 13010434107.

It is not an unprimeable number, because it can be changed into a prime (13010434133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2168405686 + ... + 2168405691.

It is an arithmetic number, because the mean of its divisors is an integer number (4336811378).

Almost surely, 2^13010434131 is an apocalyptic number.

13010434131 is a deficient number, since it is larger than the sum of its proper divisors (4336811381).

13010434131 is an equidigital number, since it uses as much as digits as its factorization.

13010434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4336811380.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13010434131 its reverse (13143401031), we get a palindrome (26153835162).

The spelling of 13010434131 in words is "thirteen billion, ten million, four hundred thirty-four thousand, one hundred thirty-one".