Search a number
-
+
130110323331 = 383522531419
BaseRepresentation
bin111100100101100101…
…1011111101010000011
3110102211121112020210010
41321023023133222003
54112431220321311
6135434415440003
712254153333502
oct1711313375203
9412747466703
10130110323331
11501a798173a
1221271826003
13c3669c1101
146423dc6839
1535b78a6da6
hex1e4b2dfa83

130110323331 has 8 divisors (see below), whose sum is σ = 175570557120. Its totient is φ = 85695152552.

The previous prime is 130110323311. The next prime is 130110323353. The reversal of 130110323331 is 133323011031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130110323331 - 26 = 130110323267 is a prime.

It is a super-2 number, since 2×1301103233312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130110323298 and 130110323307.

It is not an unprimeable number, because it can be changed into a prime (130110323311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261265461 + ... + 261265958.

It is an arithmetic number, because the mean of its divisors is an integer number (21946319640).

Almost surely, 2130110323331 is an apocalyptic number.

130110323331 is a deficient number, since it is larger than the sum of its proper divisors (45460233789).

130110323331 is an equidigital number, since it uses as much as digits as its factorization.

130110323331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 522531505.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 130110323331 its reverse (133323011031), we get a palindrome (263433334362).

The spelling of 130110323331 in words is "one hundred thirty billion, one hundred ten million, three hundred twenty-three thousand, three hundred thirty-one".

Divisors: 1 3 83 249 522531419 1567594257 43370107777 130110323331