13011113400241 has 4 divisors (see below), whose sum is σ = 14193941891184. Its totient is φ = 11828284909300.

The previous prime is 13011113400239. The next prime is 13011113400281. The reversal of 13011113400241 is 14200431111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011113400241 - 2¹ = 13011113400239 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13011113400281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591414245455 + ... + 591414245476.

It is an arithmetic number, because the mean of its divisors is an integer number (3548485472796).

Almost surely, 2^{13011113400241} is an apocalyptic number.

13011113400241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13011113400241 is a deficient number, since it is larger than the sum of its proper divisors (1182828490943).

13011113400241 is a wasteful number, since it uses less digits than its factorization.

13011113400241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1182828490942.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 13011113400241 its reverse (14200431111031), we get a palindrome (27211544511272).

The spelling of 13011113400241 in words is "thirteen trillion, eleven billion, one hundred thirteen million, four hundred thousand, two hundred forty-one".