Base | Representation |
---|---|
bin | 11000001111000011… |
… | …00100100111001011 |
3 | 1020120202202112221110 |
4 | 30013201210213023 |
5 | 203121323034430 |
6 | 5551025541403 |
7 | 640266614565 |
oct | 140741444713 |
9 | 36522675843 |
10 | 13011143115 |
11 | 55774a6443 |
12 | 26314a4863 |
13 | 12c47a3969 |
14 | 8b602a335 |
15 | 5124037b0 |
hex | 3078649cb |
13011143115 has 8 divisors (see below), whose sum is σ = 20817829008. Its totient is φ = 6939276320.
The previous prime is 13011143087. The next prime is 13011143149. The reversal of 13011143115 is 51134111031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13011143115 - 212 = 13011139019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13011143091 and 13011143100.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 433704756 + ... + 433704785.
It is an arithmetic number, because the mean of its divisors is an integer number (2602228626).
Almost surely, 213011143115 is an apocalyptic number.
13011143115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13011143115 is a deficient number, since it is larger than the sum of its proper divisors (7806685893).
13011143115 is an equidigital number, since it uses as much as digits as its factorization.
13011143115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 867409549.
The product of its (nonzero) digits is 180, while the sum is 21.
Adding to 13011143115 its reverse (51134111031), we get a palindrome (64145254146).
The spelling of 13011143115 in words is "thirteen billion, eleven million, one hundred forty-three thousand, one hundred fifteen".
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