Search a number
-
+
13011143115 = 35867409541
BaseRepresentation
bin11000001111000011…
…00100100111001011
31020120202202112221110
430013201210213023
5203121323034430
65551025541403
7640266614565
oct140741444713
936522675843
1013011143115
1155774a6443
1226314a4863
1312c47a3969
148b602a335
155124037b0
hex3078649cb

13011143115 has 8 divisors (see below), whose sum is σ = 20817829008. Its totient is φ = 6939276320.

The previous prime is 13011143087. The next prime is 13011143149. The reversal of 13011143115 is 51134111031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13011143115 - 212 = 13011139019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011143091 and 13011143100.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 433704756 + ... + 433704785.

It is an arithmetic number, because the mean of its divisors is an integer number (2602228626).

Almost surely, 213011143115 is an apocalyptic number.

13011143115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13011143115 is a deficient number, since it is larger than the sum of its proper divisors (7806685893).

13011143115 is an equidigital number, since it uses as much as digits as its factorization.

13011143115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 867409549.

The product of its (nonzero) digits is 180, while the sum is 21.

Adding to 13011143115 its reverse (51134111031), we get a palindrome (64145254146).

The spelling of 13011143115 in words is "thirteen billion, eleven million, one hundred forty-three thousand, one hundred fifteen".

Divisors: 1 3 5 15 867409541 2602228623 4337047705 13011143115