1301114441 has 4 divisors (see below), whose sum is σ = 1419397584. Its totient is φ = 1182831300.

The previous prime is 1301114429. The next prime is 1301114461. The reversal of 1301114441 is 1444111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301114441 - 2¹⁰ = 1301113417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1301114461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59141555 + ... + 59141576.

It is an arithmetic number, because the mean of its divisors is an integer number (354849396).

Almost surely, 2^1301114441 is an apocalyptic number.

1301114441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1301114441 is a deficient number, since it is larger than the sum of its proper divisors (118283143).

1301114441 is a wasteful number, since it uses less digits than its factorization.

1301114441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118283142.

The product of its (nonzero) digits is 192, while the sum is 20.

The square root of 1301114441 is about 36070.9639599498. The cubic root of 1301114441 is about 1091.7046639792.

Adding to 1301114441 its reverse (1444111031), we get a palindrome (2745225472).

The spelling of 1301114441 in words is "one billion, three hundred one million, one hundred fourteen thousand, four hundred forty-one".