130112001131321 has 4 divisors (see below), whose sum is σ = 141940364870544. Its totient is φ = 118283637392100.

The previous prime is 130112001131297. The next prime is 130112001131323. The reversal of 130112001131321 is 123131100211031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130112001131321 - 2²⁶ = 130111934022457 is a prime.

It is a super-3 number, since 3×130112001131321³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130112001131293 and 130112001131302.

It is not an unprimeable number, because it can be changed into a prime (130112001131323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5914181869595 + ... + 5914181869616.

It is an arithmetic number, because the mean of its divisors is an integer number (35485091217636).

Almost surely, 2^{130112001131321} is an apocalyptic number.

130112001131321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

130112001131321 is a deficient number, since it is larger than the sum of its proper divisors (11828363739223).

130112001131321 is a wasteful number, since it uses less digits than its factorization.

130112001131321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11828363739222.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 130112001131321 its reverse (123131100211031), we get a palindrome (253243101342352).

The spelling of 130112001131321 in words is "one hundred thirty trillion, one hundred twelve billion, one million, one hundred thirty-one thousand, three hundred twenty-one".