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130112205244555 = 5191369602160469
BaseRepresentation
bin11101100101011000011011…
…110001100100100010001011
3122001200121100021222021222011
4131211120123301210202023
5114023224244020311210
61140420415533440351
736256203511433362
oct3545303361444213
9561617307867864
10130112205244555
113850430492a1a6
121271474a3400b7
13577a6b38cb911
14241b6701c67d9
1510097b5096d8a
hex76561bc6488b

130112205244555 has 8 divisors (see below), whose sum is σ = 164352259256400. Its totient is φ = 98611355553696.

The previous prime is 130112205244543. The next prime is 130112205244591. The reversal of 130112205244555 is 555442502211031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130112205244555 - 215 = 130112205211787 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 684801080140 + ... + 684801080329.

It is an arithmetic number, because the mean of its divisors is an integer number (20544032407050).

Almost surely, 2130112205244555 is an apocalyptic number.

130112205244555 is a deficient number, since it is larger than the sum of its proper divisors (34240054011845).

130112205244555 is a wasteful number, since it uses less digits than its factorization.

130112205244555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1369602160493.

The product of its (nonzero) digits is 240000, while the sum is 40.

Adding to 130112205244555 its reverse (555442502211031), we get a palindrome (685554707455586).

The spelling of 130112205244555 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred five million, two hundred forty-four thousand, five hundred fifty-five".

Divisors: 1 5 19 95 1369602160469 6848010802345 26022441048911 130112205244555