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130113002131 = 718587571733
BaseRepresentation
bin111100100101101010…
…1101101101010010011
3110102211210120100101221
41321023111231222103
54112432412032011
6135434553105511
712254215161430
oct1711325555223
9412753510357
10130113002131
11501a9441322
12212726b8297
13c36741b4b8
1464244c2b87
1535b7c35971
hex1e4b56da93

130113002131 has 4 divisors (see below), whose sum is σ = 148700573872. Its totient is φ = 111525430392.

The previous prime is 130113002111. The next prime is 130113002177. The reversal of 130113002131 is 131200311031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130113002131 - 25 = 130113002099 is a prime.

It is a super-2 number, since 2×1301130021312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130113002101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9293785860 + ... + 9293785873.

It is an arithmetic number, because the mean of its divisors is an integer number (37175143468).

Almost surely, 2130113002131 is an apocalyptic number.

130113002131 is a deficient number, since it is larger than the sum of its proper divisors (18587571741).

130113002131 is an equidigital number, since it uses as much as digits as its factorization.

130113002131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18587571740.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130113002131 its reverse (131200311031), we get a palindrome (261313313162).

The spelling of 130113002131 in words is "one hundred thirty billion, one hundred thirteen million, two thousand, one hundred thirty-one".

Divisors: 1 7 18587571733 130113002131