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1301130231113 = 7118325777903
BaseRepresentation
bin10010111011110001011…
…001111011110101001001
311121101110000002010211202
4102323301121323311021
5132304203314343423
62433421520233545
7163001135324666
oct22736131736511
94541400063752
101301130231113
11461896105599
12190201a6b8b5
139590830134b
1446d91716a6d
1523ca327d728
hex12ef167bd49

1301130231113 has 4 divisors (see below), whose sum is σ = 1319456009088. Its totient is φ = 1282804453140.

The previous prime is 1301130231103. The next prime is 1301130231143. The reversal of 1301130231113 is 3111320311031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301130231113 - 28 = 1301130230857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301130231103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9162888881 + ... + 9162889022.

It is an arithmetic number, because the mean of its divisors is an integer number (329864002272).

Almost surely, 21301130231113 is an apocalyptic number.

It is an amenable number.

1301130231113 is a deficient number, since it is larger than the sum of its proper divisors (18325777975).

1301130231113 is an equidigital number, since it uses as much as digits as its factorization.

1301130231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18325777974.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1301130231113 its reverse (3111320311031), we get a palindrome (4412450542144).

The spelling of 1301130231113 in words is "one trillion, three hundred one billion, one hundred thirty million, two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 71 18325777903 1301130231113