13011401233 has 4 divisors (see below), whose sum is σ = 13053238848. Its totient is φ = 12969563620.

The previous prime is 13011401201. The next prime is 13011401243. The reversal of 13011401233 is 33210411031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011401233 - 2⁵ = 13011401201 is a prime.

It is a super-2 number, since 2×13011401233² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13011401233.

It is not an unprimeable number, because it can be changed into a prime (13011401243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20918341 + ... + 20918962.

It is an arithmetic number, because the mean of its divisors is an integer number (3263309712).

Almost surely, 2^13011401233 is an apocalyptic number.

It is an amenable number.

13011401233 is a deficient number, since it is larger than the sum of its proper divisors (41837615).

13011401233 is an equidigital number, since it uses as much as digits as its factorization.

13011401233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41837614.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13011401233 its reverse (33210411031), we get a palindrome (46221812264).

The spelling of 13011401233 in words is "thirteen billion, eleven million, four hundred one thousand, two hundred thirty-three".