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1301200003331 = 2731074764433
BaseRepresentation
bin10010111011110101100…
…100000110000100000011
311121101121212100221022222
4102323311210012010003
5132304324200101311
62433432451521255
7163002643352354
oct22736544060403
94541555327288
101301200003331
11461921530488
121902212b922b
13959198c0297
1446d9aab9d2b
1523ca9461adb
hex12ef5906103

1301200003331 has 4 divisors (see below), whose sum is σ = 1301205040872. Its totient is φ = 1301194965792.

The previous prime is 1301200003321. The next prime is 1301200003333. The reversal of 1301200003331 is 1333000021031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301200003331 - 218 = 1301199741187 is a prime.

It is a super-2 number, since 2×13012000033312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301200003333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2109110 + ... + 2655323.

It is an arithmetic number, because the mean of its divisors is an integer number (325301260218).

Almost surely, 21301200003331 is an apocalyptic number.

1301200003331 is a deficient number, since it is larger than the sum of its proper divisors (5037541).

1301200003331 is an equidigital number, since it uses as much as digits as its factorization.

1301200003331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5037540.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1301200003331 its reverse (1333000021031), we get a palindrome (2634200024362).

The spelling of 1301200003331 in words is "one trillion, three hundred one billion, two hundred million, three thousand, three hundred thirty-one".

Divisors: 1 273107 4764433 1301200003331