Base | Representation |
---|---|
bin | 111100100101111000… |
… | …0100110110100100001 |
3 | 110102212021211112000020 |
4 | 1321023300212310201 |
5 | 4112441213131001 |
6 | 135435404144053 |
7 | 12254332123122 |
oct | 1711360466441 |
9 | 412767745006 |
10 | 130120052001 |
11 | 50202416a65 |
12 | 21274b38029 |
13 | c368a19314 |
14 | 64253da049 |
15 | 35b8679736 |
hex | 1e4bc26d21 |
130120052001 has 4 divisors (see below), whose sum is σ = 173493402672. Its totient is φ = 86746701332.
The previous prime is 130120051969. The next prime is 130120052009. The reversal of 130120052001 is 100250021031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130120052001 - 25 = 130120051969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130120052009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21686675331 + ... + 21686675336.
It is an arithmetic number, because the mean of its divisors is an integer number (43373350668).
Almost surely, 2130120052001 is an apocalyptic number.
It is an amenable number.
130120052001 is a deficient number, since it is larger than the sum of its proper divisors (43373350671).
130120052001 is an equidigital number, since it uses as much as digits as its factorization.
130120052001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43373350670.
The product of its (nonzero) digits is 60, while the sum is 15.
Adding to 130120052001 its reverse (100250021031), we get a palindrome (230370073032).
The spelling of 130120052001 in words is "one hundred thirty billion, one hundred twenty million, fifty-two thousand, one".
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